The hybridization states of boron and nitrogen in borazole respectively

Options

A. sp, sp
B. sp, `sp^(2)`
C. `sp^(2),sp^(2)`
D. `sp^(2),sp^(3)`

Answer

To determine the hybridization states of boron and nitrogen in borazole (also known as borazine), we can follow these steps:

### Step 1: Understand the Structure of Borazole
Borazole has a cyclic structure similar to benzene, consisting of alternating boron (B) and nitrogen (N) atoms. The formula for borazole is B3N3H6, indicating that it contains three boron atoms and three nitrogen atoms.

**Hint:** Look at the molecular structure of borazole to identify the bonding arrangement of atoms.

### Step 2: Analyze the Bonding of Boron
In borazole, each boron atom is bonded to one nitrogen atom and one hydrogen atom. This means that each boron atom is involved in three bonds (two single bonds and one bond with the nitrogen).

**Hint:** Count the number of bonds around each boron atom to determine its hybridization.

### Step 3: Determine the Hybridization of Boron
Since each boron atom forms three bonds, we can deduce that the hybridization state of boron is **sp²**. This is because sp² hybridization involves one s orbital and two p orbitals, forming three equivalent sp² hybrid orbitals that can form sigma bonds.

**Hint:** Recall that sp² hybridization corresponds to three regions of electron density around the atom.

### Step 4: Analyze the Bonding of Nitrogen
Each nitrogen atom in borazole is bonded to two boron atoms and has one lone pair of electrons. This means that each nitrogen atom is also involved in three regions of electron density.

**Hint:** Consider the number of bonds and lone pairs around the nitrogen atom to find its hybridization.

### Step 5: Determine the Hybridization of Nitrogen
Since each nitrogen atom forms three regions of electron density (two bonds with boron and one lone pair), we can conclude that the hybridization state of nitrogen is also **sp²**.

**Hint:** Remember that the presence of lone pairs can affect the hybridization state, but in this case, it still results in sp² due to the total regions of electron density.

### Conclusion
Therefore, the hybridization states of boron and nitrogen in borazole are both **sp²**.

**Final Answer:** The hybridization states of boron and nitrogen in borazole respectively are **sp², sp²**.