Phallangeal formula of hand of man is

Options

A. `23333`
B. `03322`
C. `33332`
D. `02233`

Answer

To determine the phalangeal formula of the hand of a man, we need to analyze the structure of the hand and the distribution of the phalanges. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Components of the Hand
The human hand consists of several bones, including the carpals (wrist bones), metacarpals (bones of the hand), and phalanges (bones of the fingers). The phalanges are further divided into three types: proximal, intermediate (or middle), and distal phalanges.

### Step 2: Identify the Phalanges in the Hand
- Each finger (except the thumb) has three phalanges: proximal, intermediate, and distal.
- The thumb has two phalanges: proximal and distal.

### Step 3: Count the Phalanges
- For the thumb: 2 phalanges (1 proximal + 1 distal)
- For each of the four fingers: 3 phalanges each (1 proximal + 1 intermediate + 1 distal)

So, let's calculate:
- Thumb: 2 phalanges
- Four fingers: 4 fingers × 3 phalanges = 12 phalanges

### Step 4: Combine the Counts
Now, we combine the counts from the thumb and the four fingers:
- Total phalanges = 2 (thumb) + 12 (four fingers) = 14 phalanges

### Step 5: Write the Phalangeal Formula
The phalangeal formula for the hand of a man can be expressed as:
- 2 (for the thumb) + 3 (for the index finger) + 3 (for the middle finger) + 3 (for the ring finger) + 3 (for the little finger)

Thus, the phalangeal formula can be written as:
**2-3-3-3-3**

### Final Answer:
The phalangeal formula of the hand of man is **2-3-3-3-3**.

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