Home
Class 12
PHYSICS
100 g of ice (latent heat 80 cai g^(-1),...

100 g of ice (latent heat 80 cai `g^(-1)`, at `0^(@)C`) is mixed with 100 g of water (specific heat 1 cai `g^(-1) “^(@)C^(-1)`) at `80^(@)C`. The final temperature of the mixture will be

A

`0^(@)C`

B

`40^(@)C`

C

`80^(@)C`

D

`lt0^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN|Exercise Basic Maths (Thermal Physics) (Mode of Heat Transfer)|14 Videos

  • RACE

    ALLEN|Exercise Basic Maths (Thermal Physics) (Kinetic theory of gasess)|12 Videos

  • RACE

    ALLEN|Exercise Basic Maths (Thermal Physics) (Temperature scales & thermal expansion)|13 Videos

  • NEWTONS LAWS OF MOTION

    ALLEN|Exercise EXERCISE-III|28 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

100 g of ice (latent heat 80 cal/g, at 0^(@)C ) is mixed with 100 g of water (specific heat 1" cal"//g-""^(@)C ) at 80^(@)C . The final temperature of the mixture will be :-

120 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C . Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/ g-.^(@)C . The final temperature of the mixture is

500g of ice at 0°C is mixed with 1g steam at 100°C . The final temperature of the mixture is

What mass of a liquid A of specific heat capacity 0.84 J g^(-1) K^(-1) at a temperature 40^@ C must be mixed with 100 g of a liquid B of specific heat capacity 2.1 J g^(-1) K^(-1) at 20^@ C, so that the final temperature of mixture becomes 32^@ C ?

540 g of ice at 0^(@)C is mixed with 540 g of water at 80^(@)C . The final temperature of the mixture is

100g of ice at 0^(@) is mixed with 100g of water at 100^(@)C . What will be the final temperature of the mixture?

80 g of water at 30^(@) C is mixed with 50 g of water at 60^(@) C , final temperature of mixture will be

100g ice at 0^(@)C is mixed with 100g water at 100^(@)C . The resultant temperature of the mixture is

1 kg of ice at 0^(@)C is mixed with 1.5 kg of water at 45^(@)C [latent heat of fusion = 80 cal//gl. Then

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)