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One mole of hydrogen, assumed to be idea...

One mole of hydrogen, assumed to be ideal, is adiabatically expanded from its initial state `(P_(1), V_(1), T_(1))` to the final state `(P_(2), V_(2), T_(2))`. The decrease in the internal energy of the gas during this process will be given by

A

`C_(V)(T_(1)-T_(2))`

B

`C_(P)(T_(1)-T_(2))`

C

`(C_(P)+C_(V))/(2)(T_(1)-T_(2))`

D

`(C_(P)-C_(V))(T_(1)-T_(2))`

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The correct Answer is:
To solve the problem of finding the decrease in internal energy of one mole of hydrogen during an adiabatic expansion, we can follow these steps: ### Step 1: Understand the Concept of Internal Energy The internal energy (U) of an ideal gas is related to its temperature. For an ideal gas, the change in internal energy (ΔU) can be expressed as: \[ \Delta U = n C_v \Delta T \] where: - \( n \) = number of moles of the gas - \( C_v \) = molar heat capacity at constant volume - \( \Delta T \) = change in temperature ### Step 2: Identify the Variables In this case, we have: - \( n = 1 \) mole (as given in the problem) - \( C_v \) for hydrogen (which can be calculated or looked up) - \( \Delta T = T_2 - T_1 \) (where \( T_2 \) is the final temperature and \( T_1 \) is the initial temperature) ### Step 3: Substitute the Values Since we are looking for the decrease in internal energy, we need to consider that the temperature decreases during adiabatic expansion. Therefore, we can express the change in temperature as: \[ \Delta T = T_2 - T_1 \] This means: \[ \Delta U = n C_v (T_2 - T_1) = 1 \cdot C_v (T_2 - T_1) \] ### Step 4: Account for the Decrease in Internal Energy Since the problem asks for the decrease in internal energy, we can express this as: \[ \Delta U = C_v (T_2 - T_1) \] However, since \( T_2 < T_1 \) during the expansion, we can rewrite this as: \[ \Delta U = C_v (T_2 - T_1) = -C_v (T_1 - T_2) \] ### Step 5: Final Expression Thus, the decrease in internal energy of the gas during this adiabatic process is given by: \[ \Delta U = -C_v (T_1 - T_2) \] ### Conclusion The final expression for the decrease in internal energy is: \[ \Delta U = C_v (T_1 - T_2) \]
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At 27^@C two moles of an ideal monoatomic gas occupy a volume V. The gas expands adiabatically to a volume 2V. Calculate (i) the final temperature of the gas, (ii) change in its internal energy, and (iii) the work done by the gas during this process.

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