Assume that their are 8 types of nitrogen bases are available and 500 types of amino acid are available for protein synthesis, then in genetic code each codon made up by minimum how many nitrogen base :

Options

A. 3
B. 4
C. 5
D. 2

Answer

To solve the question, we need to determine how many nitrogen bases are required to form a codon, given the hypothetical scenario of having 8 types of nitrogen bases and 500 types of amino acids.

### Step-by-Step Solution:

1. **Understanding Codons**:
- Codons are sequences of nitrogen bases that code for amino acids. In standard genetic coding, a codon is made up of three nitrogen bases (a triplet).

2. **Calculating Possible Codons**:
- The number of possible codons can be calculated using the formula:
\[ \text{Number of Codons} = (\text{Number of Nitrogen Bases})^{\text{Codon Length}} \]
- In our case, we have 8 types of nitrogen bases.

3. **Determining Codon Length**:
- We need to find the minimum codon length (number of nitrogen bases in a codon) that can produce at least 500 unique codons (since there are 500 types of amino acids).
- Let \( n \) be the number of nitrogen bases in a codon. We need to find the smallest \( n \) such that:
\[ 8^n \geq 500 \]

4. **Calculating Values**:
- Let's calculate \( 8^n \) for different values of \( n \):
- For \( n = 1 \): \( 8^1 = 8 \)
- For \( n = 2 \): \( 8^2 = 64 \)
- For \( n = 3 \): \( 8^3 = 512 \)

5. **Finding Minimum n**:
- From the calculations, we see that:
- \( 8^1 = 8 \) (not sufficient)
- \( 8^2 = 64 \) (not sufficient)
- \( 8^3 = 512 \) (sufficient)
- Therefore, the minimum number of nitrogen bases required in a codon to code for at least 500 amino acids is **3**.

### Final Answer:
The minimum number of nitrogen bases required in each codon is **3**.