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Equilibrium constant K(C) for the follow...

Equilibrium constant `K_(C)` for the following reaction at 800 K is, 4 `NH_(3)(g)hArr (1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)`.
The value of `K_(p)` for the following reaction will be
`N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)`

A

`((800K)/4)`

B

`16x(800 R)^2`

C

`[1/(4xx800R)]`

D

`((800R)^-2)/16`

Text Solution

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The correct Answer is:
C
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