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Photoelectric emission is observed from a metallic surface for frequencies `n_(1) and n_(2)` of the incident light rays `(n_(1) gt n_(2))`. If the maximum values of kinetic energy of the photoelectrons emitted in the two cases are in the ratio of `1:k`, then the threshold frequency of the metallic surface is

A

`(v_(1)-v_(2))/(k-1)`

B

`(kv_(1)-v_(2))/(k-1)`

C

`(kv_(2)-v_(1))/(k-1)`

D

`(v_(1)-v_(1))/(k)`

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The correct Answer is:
B
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