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If y=log(e)x+sinx+e^(x)" then "(dy)/(dx)...

If `y=log_(e)x+sinx+e^(x)" then "(dy)/(dx)` is

A

`1/x +sin x+ e^(x)`

B

`-(1)/(x^(2))-cos x +e^(x)`

C

`1/x+ cos x+e^(x)`

D

`-(1)/(x^(2))-sin +e^(x)`

Text Solution

Verified by Experts

The correct Answer is:
C

`y=log _(e) x+sin x+ e^(x)`
`(dy)/(dx) =(d)/(dx) (log _(c)x)+ (d)/(dx)(sin x) +(d)/(dx)(e^(x))`
`=1/x +cos x+e^(x)`
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