In which of the following options all species contain X–O–X bonds in structure (X = central atom)

Options

A. `H_(2)S_(2) O_(5), S_(3)O_(9), S_(2)O_(6)^(-2)`
B. `P_(4)O_(10), P_(4)O_(6), H_(3)P_(3)O_(9)`
C. `N_(2)O_(5), N_(2)O, N_(2)O_(4)`
D. `H_(4)P_(2)O_(7), H_(4)P_(2)O_(6), H_(4)P_(2)O_(5)`

Answer

To determine which option contains all species with X–O–X bonds in their structure, we will analyze each option step by step. Here, X represents the central atom in the species.

### Step-by-Step Solution:

1. **Identify the Options**: We have four options, each containing three species. We need to check each species in the options for the presence of X–O–X bonds.

2. **Analyze the First Option**:
- **Species 1: H2S2O5 (Pyrosulfuric Acid)**
Structure: Contains S–O bonds and S–S bonds, but no X–O–X bonds.
Conclusion: **Does not contain X–O–X bonds.**

- **Species 2: S3O9**
Structure: Contains S–O–S bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

- **Species 3: S2O6^2-**
Structure: Contains S–O bonds and S–S bonds, but no X–O–X bonds.
Conclusion: **Does not contain X–O–X bonds.**

**Overall Conclusion for Option 1**: Only one species contains X–O–X bonds. **Not a valid option.**

3. **Analyze the Second Option**:
- **Species 1: P4O10**
Structure: Contains P–O–P bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

- **Species 2: P4O6**
Structure: Contains P–O–P bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

- **Species 3: H3P3O9**
Structure: Contains P–O–P bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

**Overall Conclusion for Option 2**: All three species contain X–O–X bonds. **Valid option.**

4. **Analyze the Third Option**:
- **Species 1: N2O5**
Structure: Contains N–O–N bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

- **Species 2: N2O**
Structure: Contains N–N bonds and does not have X–O–X bonds.
Conclusion: **Does not contain X–O–X bonds.**

- **Species 3: N2O4**
Structure: Contains N–N bonds and does not have X–O–X bonds.
Conclusion: **Does not contain X–O–X bonds.**

**Overall Conclusion for Option 3**: Only one species contains X–O–X bonds. **Not a valid option.**

5. **Analyze the Fourth Option**:
- **Species 1: H4P2O7**
Structure: Contains P–O–P bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

- **Species 2: H4P2O6**
Structure: Contains P–P bonds and does not have X–O–X bonds.
Conclusion: **Does not contain X–O–X bonds.**

- **Species 3: H4P2O5**
Structure: Contains P–O–P bonds (X–O–X), which is valid.
Conclusion: **Contains X–O–X bonds.**

**Overall Conclusion for Option 4**: Only two species contain X–O–X bonds. **Not a valid option.**

### Final Conclusion:
The only valid option where all species contain X–O–X bonds is **Option 2: P4O10, P4O6, H3P3O9**.

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