Product formed when `PCl_(5)` react with conc. `H_(2)SO_(4)`.

Options

A. `SOCl_(2) `
B. `SO_(2)Cl_(2)`
C. `S_(2)Cl_(2)`
D. `SO_(2)`

Explanation

To determine the product formed when phosphorus pentachloride (PCl₅) reacts with concentrated sulfuric acid (H₂SO₄), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are phosphorus pentachloride (PCl₅) and concentrated sulfuric acid (H₂SO₄).

### Step 2: Write the Reaction
When PCl₅ reacts with concentrated H₂SO₄, the reaction can be represented as follows:

\[ \text{PCl}_5 + \text{H}_2\text{SO}_4 \rightarrow \text{SO}_2\text{Cl}_2 + \text{HCl} + \text{POCl}_3 \]

### Step 3: Identify the Products
From the reaction, we can see that the products formed are:
- Sulfuryl chloride (SO₂Cl₂)
- Phosphoryl chloride (POCl₃)
- Hydrogen chloride (HCl)

### Step 4: Balance the Reaction
To ensure that the reaction is balanced, we need to check that the number of atoms of each element on the reactant side is equal to the number on the product side. The balanced equation can be written as:

\[ \text{PCl}_5 + \text{H}_2\text{SO}_4 \rightarrow \text{SO}_2\text{Cl}_2 + \text{POCl}_3 + \text{HCl} \]

### Step 5: Conclusion
From the balanced reaction, we can conclude that the main product formed when PCl₅ reacts with concentrated H₂SO₄ is sulfuryl chloride (SO₂Cl₂).

### Final Answer
The product formed is **sulfuryl chloride (SO₂Cl₂)**.

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