Product formed when excess `Cl_(2)` reacts with `NH_(3)`

Options

A. `NCl_(3)`
B. `H_(2)N - NH_(2)`
C. `N_(2)`
D. `NH_(4)Cl`

Explanation

To determine the product formed when excess chlorine (Cl₂) reacts with ammonia (NH₃), we can follow these steps:

### Step 1: Understand the Reactants
We have two reactants:
- Ammonia (NH₃)
- Chlorine (Cl₂)

### Step 2: Identify the Reaction
When ammonia reacts with chlorine, it can lead to the formation of ammonium chloride (NH₄Cl) and nitrogen gas (N₂) initially. However, since we have excess chlorine, further reactions will occur.

### Step 3: Write the Balanced Reaction for Ammonia and Chlorine
The initial reaction can be represented as:
\[ 3 \text{Cl}_2 + 2 \text{NH}_3 \rightarrow 3 \text{HCl} + \text{N}_2 \]
This shows that ammonia reacts with chlorine to produce hydrochloric acid (HCl) and nitrogen gas (N₂).

### Step 4: Consider Excess Chlorine
Since chlorine is in excess, it will continue to react with the products formed. The excess chlorine can react with ammonia to form nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

### Step 5: Write the Final Balanced Reaction
The final reaction considering excess chlorine can be represented as:
\[ 3 \text{Cl}_2 + 2 \text{NH}_3 \rightarrow 2 \text{NCl}_3 + 6 \text{HCl} \]

### Conclusion
Thus, when excess chlorine reacts with ammonia, the products formed are nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

### Final Answer
The product formed when excess Cl₂ reacts with NH₃ is nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

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