`underset(("Hydrated salt"))((A)) underset("heated")overset("Storngly")tounderset("glassy bead")underset("transparent")ubrace(B+C)`
`H_(3)BO_(3) underset("heated")overset("Strongly")toC+D`
Identify C-

Options

A. `(BN)_(x)`
B. `NaPO_(3)`
C. `B_(2)O_(3)`
D. `Mg(NH_(4))PO_(4)`

Answer

To identify compound C in the given reactions, we will analyze the two reactions step by step.

### Step 1: Analyze the first reaction
The first reaction involves a hydrated salt (compound A) that, when heated strongly, produces two products: a transparent glassy bead (compound B) and another compound (compound C).

- **Hydrated Salt (A)**: Let's assume it is Sodium Tetraborate Decahydrate, which has the formula \( Na_2B_4O_7 \cdot 10H_2O \).
- **Heating Reaction**: When heated, this hydrated salt decomposes to form:
\[ Na_2B_4O_7 \cdot 10H_2O \xrightarrow{\text{heat}} 2 NaBO_2 + B_2O_3 \]

From this reaction:
- **Compound B**: \( NaBO_2 \) (Sodium Metaborate)
- **Compound C**: \( B_2O_3 \) (Boron Trioxide)

### Step 2: Analyze the second reaction
The second reaction involves the compound \( H_3BO_3 \) (Boric Acid), which when strongly heated, produces compound C and another product (compound D).

- **Heating Reaction**: The reaction can be written as:
\[ H_3BO_3 \xrightarrow{\text{heat}} B_2O_3 + H_2O \]

From this reaction:
- **Compound C**: Again, we find \( B_2O_3 \) (Boron Trioxide)
- **Compound D**: \( H_2O \) (Water)

### Conclusion
From both reactions, we can conclude that compound C is \( B_2O_3 \) (Boron Trioxide).

### Final Answer
**C = \( B_2O_3 \)**

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