When excess amount of `NH_(3)` is reagent with `Cl_(2)` gives :-

Options

A. `NH_(4)Cl`
B. `N_(2)`
C. `NCl_(3)`
D. (1) & (2) both

Answer

To solve the question regarding the reaction between excess ammonia (NH₃) and chlorine (Cl₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are ammonia (NH₃) and chlorine (Cl₂).

2. **Understand the Reaction Conditions**: The question specifies that there is an excess amount of ammonia. This is important because it will influence the products formed.

3. **Write the Reaction**: When chlorine reacts with ammonia, especially in excess ammonia, the reaction can be represented as:
\[ 3 \text{NH}_3 + \text{Cl}_2 \rightarrow 3 \text{NH}_4\text{Cl} + \text{N}_2 \]
In this reaction, chlorine reacts with ammonia to produce ammonium chloride (NH₄Cl) and nitrogen gas (N₂).

4. **Identify the Products**: From the balanced equation, we can see that the products of the reaction are:
- Ammonium chloride (NH₄Cl)
- Nitrogen gas (N₂)

5. **Conclusion**: Therefore, when excess NH₃ is reacted with Cl₂, the products formed are ammonium chloride and nitrogen gas.

### Final Answer:
The products of the reaction between excess NH₃ and Cl₂ are ammonium chloride (NH₄Cl) and nitrogen gas (N₂).

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