How many minimum meiosis divisions are essential for the formation of 128 zygotes in human ?

Options

A. 126
B. 160
C. 131
D. 63

Answer

To determine the minimum number of meiosis divisions necessary for the formation of 128 zygotes in humans, we can break down the problem into steps:

### Step 1: Understand the formation of gametes
- In humans, meiosis is the process that produces gametes (sperm and eggs).
- One meiotic division in females results in one egg (female gamete).
- One meiotic division in males results in four sperm (male gametes).

### Step 2: Calculate the number of female gametes needed
- To form 128 zygotes, we need 128 female gametes because each zygote is formed from one egg and one sperm.
- Therefore, the number of meiotic divisions needed for females is equal to the number of zygotes:
- **Female meiotic divisions = 128**

### Step 3: Calculate the number of male gametes needed
- Each zygote also requires one sperm. Since one meiotic division in males produces four sperm, we can calculate the number of meiotic divisions needed for males:
- **Number of male gametes needed = 128**
- **Meiotic divisions needed for males = 128 / 4 = 32**

### Step 4: Total meiotic divisions required
- Now, we add the meiotic divisions required for both females and males:
- **Total meiotic divisions = Female meiotic divisions + Male meiotic divisions**
- **Total meiotic divisions = 128 + 32 = 160**

### Conclusion
- Therefore, the minimum number of meiosis divisions essential for the formation of 128 zygotes in humans is **160**.