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In the circuit shown the average power d...


In the circuit shown the average power developed in the resistor `R_(1)` is

A

31.25 W

B

62.50 W

C

125 W

D

250 W

Text Solution

Verified by Experts

The correct Answer is:
B
Rms current through resistor `R_(1)` is is
`l_(1(rms))=(50)/(sqrt(2)xx10sqrt(2))=(5)/(2)A`
`therefore` Average power developed in the resistor `R_(1)` is
`P_(1)=l_(1(rms))^(2)R_(1)=((5)/(2))^(2)10=(250)/(4)=62.50W`
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