Home
Class 12
PHYSICS
Velocity of a body of mass 2kg moving in...

Velocity of a body of mass `2kg` moving in `x-y` plane is given by `vecv=(2hati+4thatj)m//s`, where `t` is the time in second. The power delivered to the body by the resultant force acting on it at `t=5sec` is.

A

`80 m//s^(2)`

B

`160 m//s^(2)`

C

`40 m//s^(2)`

D

`100 m//s^(2)`

Text Solution

Verified by Experts

`"Power"=(d(K.E.))/(dt)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The position (x) of body moving along x-axis at time (t) is given by x=3f^(2) where x is in matre and t is in second. If mass of body is 2 kg, then find the instantaneous power delivered to body by force acting on it at t=4 s.

A particle of mass 1 kg moves in a circular path of radius 1 m such that its speed varies with time as per equation v=3t^(2)m//s where time t is in seconds. The power delivered by the force acting on the paritcle at t=1s , is :-

The position of a particle is expressed as vecr = ( 4t^(2) hati + 2thatj) m, where t is time in second. Find the velocity o the particle at t = 3 s

The position of a particle is expressed as vecr = ( 4t^(2)hati + 2thatj) m. where t is time in second. Find the acceleration of the particle.

The velocity of a block of mass 2kg moving along x- axis at any time t is givne by v=20-10t(m//s) where t is in seconds and v is in m//s . At time t=0 , the block is moving in positive x- direction. The Kinetic energy of block at t=3 sec. is :

The velocity of a block of mass 2kg moving along x- axis at any time t is givne by v=20-10t(m//s) where t is in seconds and v is in m//s . At time t=0 , the block is moving in positive x- direction. The power due to net force on force on block at t=3 sec. is :

The potential energy of body of mass 2 kg moving along the x-axis is given by U = 4x^2 , where x is in metre. Then the time period of body (in second) is

A body of mass 6kg is under a force which causes displacement in it given by S= (t^(2))/(4) maters where t is time . The work done by the force in 2 sec is

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .