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Find the remainder ( 16^(200) + 5)/( 15)...

Find the remainder `( 16^(200) + 5)/( 15)`
(a)6
(b)7
(c)10
(d)12

A

6

B

7

C

10

D

12

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the remainder when \( \frac{16^{200} + 5}{15} \), we can follow these steps: ### Step 1: Simplify \( 16^{200} \mod 15 \) First, we need to find the value of \( 16^{200} \) modulo \( 15 \). Notice that: \[ 16 \equiv 1 \mod 15 \] This is because when you divide \( 16 \) by \( 15 \), the remainder is \( 1 \). ### Step 2: Calculate \( 16^{200} \mod 15 \) Since \( 16 \equiv 1 \mod 15 \), we can raise both sides to the power of \( 200 \): \[ 16^{200} \equiv 1^{200} \mod 15 \] Calculating \( 1^{200} \): \[ 1^{200} = 1 \] Thus, we have: \[ 16^{200} \equiv 1 \mod 15 \] ### Step 3: Add 5 to the result Now we add \( 5 \) to \( 16^{200} \): \[ 16^{200} + 5 \equiv 1 + 5 \mod 15 \] Calculating this gives: \[ 1 + 5 = 6 \] ### Step 4: Find the remainder when divided by 15 Now, we need to find the remainder when \( 6 \) is divided by \( 15 \): \[ 6 \mod 15 = 6 \] ### Conclusion Thus, the remainder when \( 16^{200} + 5 \) is divided by \( 15 \) is \( 6 \). The correct answer is (a) 6. ---
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PUNEET DOGRA-BINOMIAL THEOREM-PREV YEAR QUESTIONS
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  16. The value of : [ C ( 7,0) + C ( 7,1) + C ( 7,2) ]+"........."+[C ( 7,6...

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  17. Consider the expansion of ( 1+ x)^(2n+1) The expansion of ( x-y)^(n)...

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  18. Consider the expansion of ( 1+ x)^(2n+1) What is ""^(47)C(4) + ""^(...

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  19. Consider the expansion of ( 1+ x)^(2n+1) The coefficient of x^(99) ...

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  20. Consider the expansion ( x^(2) + ( 1)/( x))^(15) What is the indepe...

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  21. Consider the expansion ( x^(2) + ( 1)/( x))^(15) The sum of the coef...

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