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In the argand plane the compex number z=...

In the argand plane the compex number z=4-3i is turned in the clockwise sense through `180^(@)` and stretched three times. The complex number represented by the new number is

A

`12+ 9i`

B

`12-9i`

C

`-12-9i`

D

`-12+9i`

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The correct Answer is:
To solve the problem step-by-step, we need to perform the following operations on the complex number \( z = 4 - 3i \): 1. **Rotate the complex number \( z \) by \( 180^\circ \) in the clockwise direction.** 2. **Stretch the resulting complex number by a factor of 3.** ### Step 1: Rotate \( z \) by \( 180^\circ \) To rotate a complex number \( z \) by \( 180^\circ \), we can multiply it by \( e^{-i\pi} \). The value of \( e^{-i\pi} \) can be calculated using Euler's formula: \[ e^{-i\pi} = \cos(-\pi) + i\sin(-\pi) = -1 + 0i = -1 \] Now we multiply \( z \) by \( -1 \): \[ z_1 = -1 \cdot (4 - 3i) = -4 + 3i \] ### Step 2: Stretch the resulting complex number by a factor of 3 To stretch the complex number \( z_1 \) by a factor of 3, we multiply it by 3: \[ z_{new} = 3 \cdot (-4 + 3i) = -12 + 9i \] ### Final Result The new complex number after rotating \( z \) by \( 180^\circ \) and stretching it by a factor of 3 is: \[ z_{new} = -12 + 9i \]
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