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If 1, omega, omega^(2) are the cube root...

If `1, omega, omega^(2)` are the cube roots of unity, then `( 1+ omega) ( 1+ omega^(2)) ( 1+ omega^(3)) ( 1+ omega + omega^(2))` is equal to `:`

A

A)`-2`

B

B)`-1`

C

C)0

D

D)2

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The correct Answer is:
To solve the problem, we need to evaluate the expression: \[ (1 + \omega)(1 + \omega^2)(1 + \omega^3)(1 + \omega + \omega^2) \] where \(1, \omega, \omega^2\) are the cube roots of unity. ### Step 1: Identify the cube roots of unity The cube roots of unity are defined as the solutions to the equation \(x^3 = 1\). The roots are: - \(1\) - \(\omega = e^{2\pi i / 3}\) - \(\omega^2 = e^{4\pi i / 3}\) ### Step 2: Use properties of cube roots of unity From the properties of cube roots of unity, we know: - \(1 + \omega + \omega^2 = 0\) - \(\omega^3 = 1\) ### Step 3: Evaluate \(1 + \omega^3\) Since \(\omega^3 = 1\): \[ 1 + \omega^3 = 1 + 1 = 2 \] ### Step 4: Evaluate \(1 + \omega + \omega^2\) From the property we mentioned: \[ 1 + \omega + \omega^2 = 0 \] ### Step 5: Substitute into the expression Now we can substitute back into our expression: \[ (1 + \omega)(1 + \omega^2)(1 + \omega^3)(1 + \omega + \omega^2) = (1 + \omega)(1 + \omega^2)(2)(0) \] ### Step 6: Simplify the expression Since we have a multiplication by \(0\): \[ (1 + \omega)(1 + \omega^2)(2)(0) = 0 \] ### Final Result Thus, the value of the expression is: \[ \boxed{0} \] ---
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