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For positive whole number of n, what is ...

For positive whole number of n, what is the value of `i^(4n+1)` ?

A

A)1

B

B)`-1`

C

C)i

D

D)`-i`

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AI Generated Solution

The correct Answer is:
To find the value of \( i^{4n+1} \) for a positive whole number \( n \), we can follow these steps: ### Step 1: Understand the powers of \( i \) The imaginary unit \( i \) is defined as \( i = \sqrt{-1} \). The powers of \( i \) cycle every four terms: - \( i^1 = i \) - \( i^2 = -1 \) - \( i^3 = -i \) - \( i^4 = 1 \) ### Step 2: Break down the exponent \( 4n + 1 \) We can express \( i^{4n+1} \) as: \[ i^{4n+1} = i^{4n} \cdot i^1 \] ### Step 3: Simplify \( i^{4n} \) Since \( i^4 = 1 \), we can use this to simplify \( i^{4n} \): \[ i^{4n} = (i^4)^n = 1^n = 1 \] ### Step 4: Combine the results Now substituting back into our expression: \[ i^{4n+1} = i^{4n} \cdot i^1 = 1 \cdot i = i \] ### Conclusion Thus, the value of \( i^{4n+1} \) is: \[ \boxed{i} \]
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