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Equation of a circle passing through origin is `x^(2) + y^(2) - 6x + 2 y = 0`. What is the equation of one of its diameter ?

A

x + 3y =0

B

x + y = 0

C

Both (a) and (b)

D

3x - y = 0

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The correct Answer is:
A
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PUNEET DOGRA-CIRCLE -PREV YEAR QUESTIONS
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  5. The equation of the circle which passes through the points (1,0) , (0,...

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  6. The two circle x^(2) + y^(2) = r^(2) and x^(2) + y^(2) - 10 x + 16 = 0...

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  7. What is the equation of the circle which passes through the points (3 ...

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  8. What is the radius of the passing through the point (2 ,4) and having ...

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  9. Consider the two circles (x-1)^(2) + (y-3)^(2) = r^(2) and x^(2) + y...

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  10. Consider the two circles (x-1)^(2) + (y-3)^(2) = r^(2) and x^(2) + y^(...

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  12. Consider a circle passing through the origin and the points (a, b) and...

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  14. A straight line x=y+2 touches the circle 4(x^2+y^2)=r^2 , The value of...

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  15. If the centre of the circle passing through the origin is (3,4). th...

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  16. Consider the circles x^(2) + y^(2) + 2ax + c = 0 and x^(2) + y^(2) + 2...

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  17. Consider the circles x^(2) + y^(2) + 2ax + c = 0 and x^(2) + y^(2) + 2...

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  18. The radius of the circle x^(2) + y^(2) + x + c = 0 passing through the...

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  19. Which one of the following points lies inside a circle of radius 6 and...

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  20. What is the radius of the circle touching x-axis at (3,0) and y-axis ...

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  21. What is the equation to circle which touchs both the axes and has cen...

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