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Let E be the ellipse (x^(2))/(9)+(y^(2))...

Let E be the ellipse `(x^(2))/(9)+(y^(2))/(4)=1` and C be the circle `x^(2)+y^(2)=9`. If P = (1,2), then which one of the following is correct?

A

Q lies inside C but outside E

B

Q lies outside both C and E

C

P lies inside both C and E

D

P lies inside C but outside E

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the position of the point P = (1, 2) in relation to the given ellipse E and circle C. ### Step-by-Step Solution: 1. **Identify the equations of the ellipse and the circle:** - The equation of the ellipse \( E \) is given by: \[ \frac{x^2}{9} + \frac{y^2}{4} = 1 \] - The equation of the circle \( C \) is given by: \[ x^2 + y^2 = 9 \] 2. **Substitute the coordinates of point P into the circle's equation:** - The coordinates of point P are \( (1, 2) \). - Substitute \( x = 1 \) and \( y = 2 \) into the circle's equation: \[ 1^2 + 2^2 = 1 + 4 = 5 \] - Since \( 5 < 9 \), point P lies **inside the circle**. 3. **Substitute the coordinates of point P into the ellipse's equation:** - Substitute \( x = 1 \) and \( y = 2 \) into the ellipse's equation: \[ \frac{1^2}{9} + \frac{2^2}{4} = \frac{1}{9} + \frac{4}{4} = \frac{1}{9} + 1 = \frac{1}{9} + \frac{9}{9} = \frac{10}{9} \] - Since \( \frac{10}{9} > 1 \), point P lies **outside the ellipse**. 4. **Conclusion:** - Point P lies inside the circle and outside the ellipse. Therefore, the correct statement is: - Point P lies inside circle C but outside ellipse E.
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