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Which is the largest of the fol lowing f...

Which is the largest of the fol lowing fractions ?
`(2)/(3),(3)/(5),(8)/(11),(11)/(17)`

A

`(8)/(11)`

B

`(3)/(5)`

C

`(11)/(17)`

D

`(2)/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the fractions \(\frac{2}{3}, \frac{3}{5}, \frac{8}{11}, \frac{11}{17}\) is the largest, we can compare them using cross multiplication. Here’s a step-by-step solution: ### Step 1: Compare \(\frac{2}{3}\) and \(\frac{3}{5}\) To compare \(\frac{2}{3}\) and \(\frac{3}{5}\), we can cross-multiply: \[ 2 \times 5 = 10 \] \[ 3 \times 3 = 9 \] Since \(10 > 9\), we conclude that: \[ \frac{2}{3} > \frac{3}{5} \] ### Step 2: Compare \(\frac{2}{3}\) and \(\frac{8}{11}\) Next, we compare \(\frac{2}{3}\) and \(\frac{8}{11}\): \[ 2 \times 11 = 22 \] \[ 3 \times 8 = 24 \] Since \(22 < 24\), we conclude that: \[ \frac{8}{11} > \frac{2}{3} \] ### Step 3: Compare \(\frac{8}{11}\) and \(\frac{11}{17}\) Now, we compare \(\frac{8}{11}\) and \(\frac{11}{17}\): \[ 8 \times 17 = 136 \] \[ 11 \times 11 = 121 \] Since \(136 > 121\), we conclude that: \[ \frac{8}{11} > \frac{11}{17} \] ### Conclusion After comparing all fractions, we find that: \[ \frac{8}{11} > \frac{2}{3}, \quad \frac{8}{11} > \frac{3}{5}, \quad \frac{8}{11} > \frac{11}{17} \] Thus, the largest fraction among the given options is: \[ \boxed{\frac{8}{11}} \]
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