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If the difference between the reciprocal...

If the difference between the reciprocal of a positive proper frac tion and the fraction itself be `(9)/(20)` then the fraction is

A

`(3)/(5)`

B

`(3)/(10)`

C

`(4)/(5)`

D

`(5)/(4)`

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The correct Answer is:
To solve the problem, we need to find a positive proper fraction \( \frac{x}{y} \) such that the difference between its reciprocal \( \frac{y}{x} \) and the fraction itself \( \frac{x}{y} \) is \( \frac{9}{20} \). ### Step-by-Step Solution: 1. **Set Up the Equation**: We start by expressing the condition given in the problem mathematically: \[ \frac{y}{x} - \frac{x}{y} = \frac{9}{20} \] 2. **Find a Common Denominator**: The common denominator for the left-hand side is \( xy \): \[ \frac{y^2 - x^2}{xy} = \frac{9}{20} \] 3. **Cross Multiply**: To eliminate the fractions, we cross multiply: \[ 20(y^2 - x^2) = 9xy \] 4. **Rearrange the Equation**: Rearranging gives us: \[ 20y^2 - 9xy - 20x^2 = 0 \] 5. **Recognize as a Quadratic Equation**: This is a quadratic equation in terms of \( y \): \[ 20y^2 - 9xy - 20x^2 = 0 \] 6. **Use the Quadratic Formula**: We can apply the quadratic formula \( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 20 \), \( b = -9x \), and \( c = -20x^2 \): \[ y = \frac{9x \pm \sqrt{(-9x)^2 - 4 \cdot 20 \cdot (-20x^2)}}{2 \cdot 20} \] 7. **Calculate the Discriminant**: Calculate the discriminant: \[ (-9x)^2 - 4 \cdot 20 \cdot (-20x^2) = 81x^2 + 1600x^2 = 1681x^2 \] 8. **Substitute Back into the Formula**: Now substitute back into the quadratic formula: \[ y = \frac{9x \pm 41x}{40} \] 9. **Find Possible Values for \( y \)**: This gives us two possible solutions for \( y \): \[ y = \frac{50x}{40} = \frac{5x}{4} \quad \text{or} \quad y = \frac{-32x}{40} = -\frac{8x}{10} \] Since \( y \) must be positive, we take \( y = \frac{5x}{4} \). 10. **Determine the Fraction**: Since \( \frac{x}{y} \) is a proper fraction, we substitute \( y \) back: \[ \frac{x}{y} = \frac{x}{\frac{5x}{4}} = \frac{4}{5} \] ### Final Answer: The fraction is \( \frac{4}{5} \).
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