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Afraction having denominator 30 and lyin...

Afraction having denominator 30 and lying between `(5)/(8) and (7)/(11)` is-

A

`(18)/(30)`

B

`(19)/(30)`

C

`(20)/(30)`

D

`(21)/(30)`

Text Solution

AI Generated Solution

The correct Answer is:
To find a fraction with a denominator of 30 that lies between \( \frac{5}{8} \) and \( \frac{7}{11} \), we can follow these steps: ### Step 1: Find the LCM of the Denominators We need to find the least common multiple (LCM) of the denominators 8, 11, and 30 to compare the fractions easily. - The prime factorization of 8 is \( 2^3 \). - The prime factorization of 11 is \( 11^1 \). - The prime factorization of 30 is \( 2^1 \times 3^1 \times 5^1 \). The LCM is found by taking the highest power of each prime: - For 2, the highest power is \( 2^3 \) (from 8). - For 3, the highest power is \( 3^1 \) (from 30). - For 5, the highest power is \( 5^1 \) (from 30). - For 11, the highest power is \( 11^1 \) (from 11). Thus, the LCM is: \[ LCM = 2^3 \times 3^1 \times 5^1 \times 11^1 = 8 \times 3 \times 5 \times 11 = 1320 \] ### Step 2: Convert the Fractions Now we convert \( \frac{5}{8} \) and \( \frac{7}{11} \) to have a common denominator of 1320. - For \( \frac{5}{8} \): \[ \frac{5}{8} = \frac{5 \times 165}{8 \times 165} = \frac{825}{1320} \] - For \( \frac{7}{11} \): \[ \frac{7}{11} = \frac{7 \times 120}{11 \times 120} = \frac{840}{1320} \] ### Step 3: Identify the Range Now we have: \[ \frac{825}{1320} < \frac{x}{30} < \frac{840}{1320} \] ### Step 4: Express the Fraction with Denominator 30 To express \( \frac{x}{30} \) with a denominator of 1320, we can find \( x \) such that: \[ \frac{x}{30} = \frac{44x}{1320} \] ### Step 5: Set Up the Inequality Now we set up the inequality: \[ 825 < 44x < 840 \] ### Step 6: Solve for \( x \) Now we solve the inequalities: 1. For the left side: \[ 825 < 44x \implies x > \frac{825}{44} \approx 18.75 \] 2. For the right side: \[ 44x < 840 \implies x < \frac{840}{44} \approx 19.09 \] ### Step 7: Determine Possible Integer Values Since \( x \) must be an integer, the only integer value that satisfies \( 18.75 < x < 19.09 \) is: \[ x = 19 \] ### Step 8: Write the Required Fraction Thus, the required fraction is: \[ \frac{19}{30} \] ### Final Answer The fraction having a denominator of 30 and lying between \( \frac{5}{8} \) and \( \frac{7}{11} \) is \( \frac{19}{30} \). ---
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