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If N=1 + 11 + 101 + 1001 + ... + 1000000...

If N=1 + 11 + 101 + 1001 + ... + 1000000001, what is the value of N ?

A

1111111100

B

1111111110

C

1111111120

D

1111111111

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AI Generated Solution

The correct Answer is:
To find the value of \( N = 1 + 11 + 101 + 1001 + ... + 1000000001 \), we can observe the pattern in the numbers being added. ### Step-by-Step Solution: 1. **Identify the Pattern**: The numbers can be expressed as: - \( 1 = 1 \) - \( 11 = 10 + 1 \) - \( 101 = 100 + 1 \) - \( 1001 = 1000 + 1 \) - ... - \( 1000000001 = 10^9 + 1 \) Each term can be represented as \( 10^k + 1 \) where \( k \) ranges from \( 0 \) to \( 9 \). 2. **Count the Terms**: There are 10 terms in total, from \( k = 0 \) to \( k = 9 \). 3. **Separate the Terms**: We can separate the \( 1 \) from each term: \[ N = (1 + 1 + 1 + ... + 1) + (10^0 + 10^1 + 10^2 + ... + 10^9) \] The first part has \( 10 \) ones (since there are 10 terms): \[ 1 + 1 + 1 + ... + 1 = 10 \] 4. **Sum the Powers of 10**: The second part is the sum of powers of \( 10 \): \[ 10^0 + 10^1 + 10^2 + ... + 10^9 \] This is a geometric series with the first term \( a = 1 \) (which is \( 10^0 \)) and the common ratio \( r = 10 \). The formula for the sum of the first \( n \) terms of a geometric series is: \[ S_n = a \frac{r^n - 1}{r - 1} \] Here, \( n = 10 \): \[ S_{10} = 1 \cdot \frac{10^{10} - 1}{10 - 1} = \frac{10^{10} - 1}{9} \] 5. **Combine the Results**: Now we can combine both parts: \[ N = 10 + \frac{10^{10} - 1}{9} \] 6. **Simplify**: To combine \( 10 \) with the fraction, we can express \( 10 \) as \( \frac{90}{9} \): \[ N = \frac{90}{9} + \frac{10^{10} - 1}{9} = \frac{90 + 10^{10} - 1}{9} = \frac{10^{10} + 89}{9} \] ### Final Answer: Thus, the value of \( N \) is: \[ N = \frac{10^{10} + 89}{9} \]
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