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If (1+(1)/(3)) (1+(1)/(5)) (1+(1)/(7)) (...

If `(1+(1)/(3)) (1+(1)/(5)) (1+(1)/(7)) (1+(1)/(9)) (1-(1)/(4)) (1-(1)/(6)) (1-(1)/(8))=1 +(1)/(x)` then what is the value of x ?

A

9

B

8

C

6

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \[ (1 + \frac{1}{3})(1 + \frac{1}{5})(1 + \frac{1}{7})(1 + \frac{1}{9})(1 - \frac{1}{4})(1 - \frac{1}{6})(1 - \frac{1}{8}) = 1 + \frac{1}{x} \] we will simplify each term step by step. ### Step 1: Simplify each term 1. **Calculate \(1 + \frac{1}{3}\)**: \[ 1 + \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{4}{3} \] 2. **Calculate \(1 + \frac{1}{5}\)**: \[ 1 + \frac{1}{5} = \frac{5}{5} + \frac{1}{5} = \frac{6}{5} \] 3. **Calculate \(1 + \frac{1}{7}\)**: \[ 1 + \frac{1}{7} = \frac{7}{7} + \frac{1}{7} = \frac{8}{7} \] 4. **Calculate \(1 + \frac{1}{9}\)**: \[ 1 + \frac{1}{9} = \frac{9}{9} + \frac{1}{9} = \frac{10}{9} \] 5. **Calculate \(1 - \frac{1}{4}\)**: \[ 1 - \frac{1}{4} = \frac{4}{4} - \frac{1}{4} = \frac{3}{4} \] 6. **Calculate \(1 - \frac{1}{6}\)**: \[ 1 - \frac{1}{6} = \frac{6}{6} - \frac{1}{6} = \frac{5}{6} \] 7. **Calculate \(1 - \frac{1}{8}\)**: \[ 1 - \frac{1}{8} = \frac{8}{8} - \frac{1}{8} = \frac{7}{8} \] ### Step 2: Combine all the simplified terms Now we can combine all the simplified fractions: \[ \frac{4}{3} \cdot \frac{6}{5} \cdot \frac{8}{7} \cdot \frac{10}{9} \cdot \frac{3}{4} \cdot \frac{5}{6} \cdot \frac{7}{8} \] ### Step 3: Cancel out common terms When we multiply these fractions, we can see that many terms will cancel out: - \(4\) in the numerator of \(\frac{4}{3}\) cancels with \(4\) in the denominator of \(\frac{3}{4}\). - \(6\) in the numerator of \(\frac{6}{5}\) cancels with \(6\) in the denominator of \(\frac{5}{6}\). - \(8\) in the numerator of \(\frac{8}{7}\) cancels with \(8\) in the denominator of \(\frac{7}{8}\). - The \(3\) in the numerator of \(\frac{3}{4}\) cancels with the \(3\) in the denominator of \(\frac{4}{3}\). - The \(5\) in the numerator of \(\frac{5}{6}\) cancels with the \(5\) in the denominator of \(\frac{6}{5}\). - The \(7\) in the numerator of \(\frac{7}{8}\) cancels with the \(7\) in the denominator of \(\frac{8}{7}\). After canceling, we are left with: \[ \frac{10}{9} \] ### Step 4: Set the equation equal to \(1 + \frac{1}{x}\) Now we set the left-hand side equal to the right-hand side: \[ \frac{10}{9} = 1 + \frac{1}{x} \] ### Step 5: Solve for \(x\) Subtract \(1\) from both sides: \[ \frac{10}{9} - 1 = \frac{1}{x} \] Convert \(1\) to a fraction with a denominator of \(9\): \[ \frac{10}{9} - \frac{9}{9} = \frac{1}{x} \] This simplifies to: \[ \frac{1}{9} = \frac{1}{x} \] Thus, we find: \[ x = 9 \] ### Final Answer The value of \(x\) is \(9\). ---
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KIRAN PUBLICATION-NUMBER SYSTEM-TEST YOURSELF
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