A tap is dripping at a constant rate into a container. The level (Lcm) of the water in the container is given by the equation `L=2-2^t` , where t is time taken in hours. Then the level of water in the container at the start is

Options

A. 0 cm
B. 1 cm
C. 2 cm
D. 4 cm

Answer

To find the level of water in the container at the start (when time \( t = 0 \)), we can use the given equation:

\[ L = 2 - 2^t \]

### Step-by-Step Solution:

1. **Identify the time at the start**:
- At the start, time \( t = 0 \).

2. **Substitute \( t = 0 \) into the equation**:
- We substitute \( t = 0 \) into the equation \( L = 2 - 2^t \):
\[ L = 2 - 2^0 \]

3. **Calculate \( 2^0 \)**:
- We know that any number raised to the power of 0 is 1:
\[ 2^0 = 1 \]

4. **Substitute back into the equation**:
- Now substitute \( 2^0 = 1 \) back into the equation:
\[ L = 2 - 1 \]

5. **Perform the subtraction**:
- Now, calculate \( 2 - 1 \):
\[ L = 1 \]

6. **Conclusion**:
- Therefore, the level of water in the container at the start is \( 1 \) centimeter.

### Final Answer:
The level of water in the container at the start is **1 centimeter**.