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Find the unit place digit in the express...

Find the unit place digit in the expression `(159)^(144)+(123)-(110)^(510)+(213)^(25)`

A

3

B

4

C

7

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To find the unit place digit in the expression \( (159)^{144} + (123) - (110)^{510} + (213)^{25} \), we will analyze each term separately and then combine the results. ### Step 1: Find the unit digit of \( (159)^{144} \) 1. The unit digit of \( 159 \) is \( 9 \). 2. The unit digits of powers of \( 9 \) follow a pattern: - \( 9^1 = 9 \) (unit digit is 9) - \( 9^2 = 81 \) (unit digit is 1) - \( 9^3 = 729 \) (unit digit is 9) - \( 9^4 = 6561 \) (unit digit is 1) The pattern repeats every 2 terms: \( 9, 1 \). 3. Since \( 144 \) is even, the unit digit of \( 9^{144} \) is the same as \( 9^2 \), which is \( 1 \). ### Step 2: Find the unit digit of \( (123) \) 1. The unit digit of \( 123 \) is \( 3 \). 2. The unit digits of powers of \( 3 \) follow a pattern: - \( 3^1 = 3 \) (unit digit is 3) - \( 3^2 = 9 \) (unit digit is 9) - \( 3^3 = 27 \) (unit digit is 7) - \( 3^4 = 81 \) (unit digit is 1) The pattern repeats every 4 terms: \( 3, 9, 7, 1 \). 3. To find the unit digit of \( 3^1 \) (since \( 123 \) is not raised to any power), the unit digit is \( 3 \). ### Step 3: Find the unit digit of \( (110)^{510} \) 1. The unit digit of \( 110 \) is \( 0 \). 2. Any power of \( 0 \) is \( 0 \), so the unit digit of \( (110)^{510} \) is \( 0 \). ### Step 4: Find the unit digit of \( (213)^{25} \) 1. The unit digit of \( 213 \) is \( 3 \). 2. We already established the pattern for \( 3 \) in Step 2. 3. To find the unit digit of \( 3^{25} \), we calculate \( 25 \mod 4 \) (since the pattern repeats every 4 terms): - \( 25 \div 4 = 6 \) remainder \( 1 \). - Thus, \( 3^{25} \) has the same unit digit as \( 3^1 \), which is \( 3 \). ### Step 5: Combine the results Now we combine the unit digits from each part of the expression: - From \( (159)^{144} \): \( 1 \) - From \( (123) \): \( 3 \) - From \( (110)^{510} \): \( 0 \) - From \( (213)^{25} \): \( 3 \) Putting it all together: \[ 1 + 3 - 0 + 3 = 7 \] ### Final Answer The unit place digit in the expression \( (159)^{144} + (123) - (110)^{510} + (213)^{25} \) is \( 7 \).
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