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The liquids, X and Y are mixed in the ra...

The liquids, X and Y are mixed in the ratio of 3:2 and the mixture is sold at Rs 11 per litre at a profit of 10%. If the liquid X costs Rs. 2 more per litre than Y, the cost of X per litre is (in Rs.)

A

10.8

B

11.75

C

9.5

D

11

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information given in the question. ### Step 1: Understand the ratio of the liquids We have two liquids, X and Y, mixed in the ratio of 3:2. This means for every 3 parts of liquid X, there are 2 parts of liquid Y. ### Step 2: Determine the selling price and profit The mixture is sold at Rs 11 per litre with a profit of 10%. To find the cost price (CP) of the mixture, we can use the formula: \[ \text{Selling Price (SP)} = \text{Cost Price (CP)} + \text{Profit} \] Given that the profit is 10% of the cost price, we can express the selling price as: \[ SP = CP + 0.1 \times CP = 1.1 \times CP \] Setting SP to Rs 11, we have: \[ 11 = 1.1 \times CP \] To find CP, we rearrange the equation: \[ CP = \frac{11}{1.1} = 10 \text{ Rs} \] ### Step 3: Set up the cost equations for liquids X and Y Let the cost of liquid Y be Rs \(y\) per litre. Since liquid X costs Rs 2 more than liquid Y, we can express the cost of liquid X as: \[ \text{Cost of X} = y + 2 \] ### Step 4: Calculate the total cost of the mixture The total cost of the mixture can be calculated based on the ratio of the liquids: - For 3 parts of X: \(3 \times (y + 2)\) - For 2 parts of Y: \(2 \times y\) The total cost of the mixture is: \[ \text{Total Cost} = 3(y + 2) + 2y = 3y + 6 + 2y = 5y + 6 \] ### Step 5: Relate the total cost to the cost price Since we found the cost price of the mixture to be Rs 10, we can set up the equation: \[ \frac{5y + 6}{5} = 10 \] Multiplying through by 5 to eliminate the fraction gives: \[ 5y + 6 = 50 \] Subtracting 6 from both sides: \[ 5y = 44 \] Dividing by 5: \[ y = \frac{44}{5} = 8.8 \text{ Rs} \] ### Step 6: Calculate the cost of liquid X Now that we have the cost of liquid Y, we can find the cost of liquid X: \[ \text{Cost of X} = y + 2 = 8.8 + 2 = 10.8 \text{ Rs} \] ### Conclusion The cost of liquid X per litre is Rs 10.8.
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