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12 litres of a mixture has wine and wate...

12 litres of a mixture has wine and water in the ratio 2: 3. How much water must be added to get wine to water ratio of 3:7 in the resultant mixture?

A

4.5litres

B

3.5litres

C

3litres

D

4litres

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the given information and apply the concept of ratios and mixtures. ### Step 1: Understand the initial mixture We have a total mixture of 12 litres, which consists of wine and water in the ratio of 2:3. ### Step 2: Calculate the quantities of wine and water in the initial mixture The total parts in the ratio 2:3 is: \[ 2 + 3 = 5 \text{ parts} \] Now, we can find the quantity of wine and water: - Quantity of wine: \[ \text{Wine} = \frac{2}{5} \times 12 = \frac{24}{5} = 4.8 \text{ litres} \] - Quantity of water: \[ \text{Water} = \frac{3}{5} \times 12 = \frac{36}{5} = 7.2 \text{ litres} \] ### Step 3: Set up the new ratio We want to change the ratio of wine to water to 3:7. Let \( x \) be the amount of water we need to add. After adding \( x \) litres of water, the new quantities will be: - Wine: 4.8 litres (remains the same) - Water: \( 7.2 + x \) litres ### Step 4: Set up the equation based on the new ratio According to the new ratio of wine to water (3:7): \[ \frac{\text{Wine}}{\text{Water}} = \frac{3}{7} \] Substituting the quantities we have: \[ \frac{4.8}{7.2 + x} = \frac{3}{7} \] ### Step 5: Cross-multiply to solve for \( x \) Cross-multiplying gives: \[ 4.8 \times 7 = 3 \times (7.2 + x) \] Calculating the left side: \[ 33.6 = 21.6 + 3x \] ### Step 6: Isolate \( x \) Now, we can isolate \( x \): \[ 33.6 - 21.6 = 3x \] \[ 12 = 3x \] \[ x = \frac{12}{3} = 4 \] ### Conclusion The amount of water that must be added is **4 litres**. ---
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