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There are two kinds of alloys of tin and...

There are two kinds of alloys of tin and copper. The first alloy contains tin and copper such that 93.33% of it is tin. In the second alloy there is 86.66% tin. What weight of the first alloy should be mixed with some weight of the second alloy so as to make a 50 kg mass containing 90% of tin?

A

15kg

B

20kg

C

30kg

D

25kg

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The correct Answer is:
To solve the problem of mixing two alloys of tin and copper to achieve a desired composition, we can use the method of alligation. Here’s a step-by-step solution: ### Step 1: Identify the percentages of tin in each alloy and the desired percentage. - First alloy: 93.33% tin - Second alloy: 86.66% tin - Desired mixture: 90% tin ### Step 2: Convert the percentages into fractions for easier calculation. - First alloy: 93.33% = \( \frac{280}{3} \)% (which is approximately 93.33%) - Second alloy: 86.66% = \( \frac{260}{3} \)% (which is approximately 86.66%) - Desired mixture: 90% = \( \frac{270}{3} \)% ### Step 3: Set up the alligation. Using the alligation method, we subtract the desired percentage from the percentages of each alloy: - Difference between first alloy and desired mixture: \[ 93.33 - 90 = 3.33 \] - Difference between second alloy and desired mixture: \[ 90 - 86.66 = 3.34 \] ### Step 4: Establish the ratio of the two alloys. The ratio of the weights of the first alloy (A) to the second alloy (B) is given by the differences calculated: \[ \text{Ratio of A to B} = \frac{3.34}{3.33} \] This simplifies approximately to: \[ \text{Ratio of A to B} \approx 1:1 \] ### Step 5: Calculate the total weight of the mixture. Let the weight of the first alloy be \( x \) kg and the weight of the second alloy be \( y \) kg. According to the problem: \[ x + y = 50 \text{ kg} \] ### Step 6: Use the ratio to express one variable in terms of the other. From the ratio \( 1:1 \), we can say: \[ x = y \] Substituting \( y \) with \( x \) in the total weight equation: \[ x + x = 50 \] \[ 2x = 50 \] \[ x = 25 \text{ kg} \] ### Step 7: Find the weight of the second alloy. Since \( x = y \): \[ y = 25 \text{ kg} \] ### Conclusion: The weight of the first alloy that should be mixed is **25 kg**. ---
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