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A student multiplied a number by 3/5 ins...

A student multiplied a number by 3/5 instead of 5/3. What will be the percentage error in the calculation?

A

64%

B

65%

C

66%

D

67%

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the percentage error when a student multiplied a number by \( \frac{3}{5} \) instead of \( \frac{5}{3} \), we can follow these steps: ### Step 1: Define the number Let the number be \( x \). For simplicity, we can assume \( x = 100 \). ### Step 2: Calculate the actual multiplication The correct multiplication should be: \[ \text{Actual Value} = x \times \frac{5}{3} = 100 \times \frac{5}{3} = \frac{500}{3} \approx 166.67 \] ### Step 3: Calculate the incorrect multiplication The student incorrectly multiplied the number by \( \frac{3}{5} \): \[ \text{Incorrect Value} = x \times \frac{3}{5} = 100 \times \frac{3}{5} = 60 \] ### Step 4: Determine the error The error in the calculation is the difference between the actual value and the incorrect value: \[ \text{Error} = \text{Actual Value} - \text{Incorrect Value} = \frac{500}{3} - 60 \] To perform this subtraction, we need to convert 60 into a fraction: \[ 60 = \frac{180}{3} \] Now, we can subtract: \[ \text{Error} = \frac{500}{3} - \frac{180}{3} = \frac{320}{3} \approx 106.67 \] ### Step 5: Calculate the percentage error The percentage error is calculated using the formula: \[ \text{Percentage Error} = \left( \frac{\text{Error}}{\text{Actual Value}} \right) \times 100 \] Substituting the values we have: \[ \text{Percentage Error} = \left( \frac{\frac{320}{3}}{\frac{500}{3}} \right) \times 100 = \left( \frac{320}{500} \right) \times 100 = \frac{32000}{500} = 64\% \] ### Final Answer The percentage error in the calculation is \( 64\% \). ---
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