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A can do (1)/(4) of a work in 10 days B ...

A can do `(1)/(4)` of a work in 10 days B can do `(1)/(3)` of the work in 20 days. In how many days can both A and B together do the work ?

A

30 days

B

32 days

C

24 days

D

25 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine how long it will take for A and B to complete the work together. ### Step 1: Determine the work rate of A A can do \( \frac{1}{4} \) of the work in 10 days. Therefore, to find out how long A takes to complete the entire work (1 unit), we can set up the following equation: \[ \text{Time taken by A to complete 1 unit} = \frac{1}{\frac{1}{4}} \times 10 = 4 \times 10 = 40 \text{ days} \] ### Step 2: Determine the work rate of B B can do \( \frac{1}{3} \) of the work in 20 days. Similarly, to find out how long B takes to complete the entire work (1 unit), we can set up the following equation: \[ \text{Time taken by B to complete 1 unit} = \frac{1}{\frac{1}{3}} \times 20 = 3 \times 20 = 60 \text{ days} \] ### Step 3: Calculate the work rates of A and B Now we can find the work rates (work done per day) for A and B: - Work rate of A: \[ \text{Work rate of A} = \frac{1 \text{ unit}}{40 \text{ days}} = \frac{1}{40} \text{ units per day} \] - Work rate of B: \[ \text{Work rate of B} = \frac{1 \text{ unit}}{60 \text{ days}} = \frac{1}{60} \text{ units per day} \] ### Step 4: Combine the work rates of A and B To find the combined work rate of A and B, we add their individual work rates: \[ \text{Combined work rate} = \frac{1}{40} + \frac{1}{60} \] To add these fractions, we need a common denominator. The least common multiple (LCM) of 40 and 60 is 120. Converting the fractions: \[ \frac{1}{40} = \frac{3}{120} \quad \text{and} \quad \frac{1}{60} = \frac{2}{120} \] Now we can add them: \[ \text{Combined work rate} = \frac{3}{120} + \frac{2}{120} = \frac{5}{120} = \frac{1}{24} \text{ units per day} \] ### Step 5: Calculate the time taken by A and B together to complete the work If A and B together can complete \( \frac{1}{24} \) units of work in one day, then the time taken to complete 1 unit of work is the reciprocal of their combined work rate: \[ \text{Time taken} = \frac{1 \text{ unit}}{\frac{1}{24} \text{ units per day}} = 24 \text{ days} \] ### Final Answer A and B together can complete the work in **24 days**. ---
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