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A and B can do a piece of work in 15 day...

A and B can do a piece of work in 15 days. B and C can do the same work in 10 days and A and C can do the same in 12 days. Time taken by A, B and C together to do the job is

A

4 days

B

9 days

C

8 days

D

5 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the time taken by A, B, and C together to complete the work based on the information given about their individual and pair work rates. ### Step-by-Step Solution: 1. **Understanding the Work Rates**: - Let the total work be represented in units. We can assume the total work is 1 unit for simplicity. - A and B can complete the work in 15 days, so their combined work rate is: \[ \text{Work rate of A and B} = \frac{1}{15} \text{ units/day} \] - B and C can complete the work in 10 days, so their combined work rate is: \[ \text{Work rate of B and C} = \frac{1}{10} \text{ units/day} \] - A and C can complete the work in 12 days, so their combined work rate is: \[ \text{Work rate of A and C} = \frac{1}{12} \text{ units/day} \] 2. **Setting Up the Equations**: - Let the work rates of A, B, and C be \( a \), \( b \), and \( c \) respectively. We can set up the following equations based on the combined work rates: \[ a + b = \frac{1}{15} \tag{1} \] \[ b + c = \frac{1}{10} \tag{2} \] \[ a + c = \frac{1}{12} \tag{3} \] 3. **Adding the Equations**: - Adding equations (1), (2), and (3) gives: \[ (a + b) + (b + c) + (a + c) = \frac{1}{15} + \frac{1}{10} + \frac{1}{12} \] - This simplifies to: \[ 2a + 2b + 2c = \frac{1}{15} + \frac{1}{10} + \frac{1}{12} \] - Dividing everything by 2: \[ a + b + c = \frac{1}{2} \left( \frac{1}{15} + \frac{1}{10} + \frac{1}{12} \right) \tag{4} \] 4. **Finding a Common Denominator**: - The least common multiple (LCM) of 15, 10, and 12 is 60. We can convert the fractions: \[ \frac{1}{15} = \frac{4}{60}, \quad \frac{1}{10} = \frac{6}{60}, \quad \frac{1}{12} = \frac{5}{60} \] - Thus: \[ \frac{1}{15} + \frac{1}{10} + \frac{1}{12} = \frac{4 + 6 + 5}{60} = \frac{15}{60} = \frac{1}{4} \] 5. **Substituting Back**: - Substituting back into equation (4): \[ a + b + c = \frac{1}{2} \cdot \frac{1}{4} = \frac{1}{8} \] 6. **Calculating Time Taken by A, B, and C Together**: - The combined work rate of A, B, and C is \( \frac{1}{8} \) units/day. Therefore, the time taken by A, B, and C together to complete the work is: \[ \text{Time} = \frac{\text{Total Work}}{\text{Combined Work Rate}} = \frac{1}{\frac{1}{8}} = 8 \text{ days} \] ### Final Answer: The time taken by A, B, and C together to do the job is **8 days**.
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