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A and B together can finish a job in 24 ...

A and B together can finish a job in 24 days, while A, B and C together can finish the same job in 8 days. C alone will finish the job in

A

12 days

B

14 days

C

16 days

D

24 days

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The correct Answer is:
To solve the problem step by step, we will break down the information given and use it to find out how long C will take to finish the job alone. ### Step-by-Step Solution: 1. **Understanding the Work Done by A and B Together:** - A and B together can finish the job in 24 days. - This means their combined work rate (efficiency) is \( \frac{1}{24} \) of the job per day. 2. **Understanding the Work Done by A, B, and C Together:** - A, B, and C together can finish the job in 8 days. - This means their combined work rate (efficiency) is \( \frac{1}{8} \) of the job per day. 3. **Calculating the Efficiency of A and B:** - Let the efficiency of A + B be \( E_{AB} = \frac{1}{24} \). - Let the efficiency of A + B + C be \( E_{ABC} = \frac{1}{8} \). 4. **Finding the Efficiency of C:** - The efficiency of C can be found by subtracting the efficiency of A and B from the efficiency of A, B, and C: \[ E_C = E_{ABC} - E_{AB} = \frac{1}{8} - \frac{1}{24} \] 5. **Finding a Common Denominator:** - The least common multiple of 8 and 24 is 24. We convert \( \frac{1}{8} \) to have a denominator of 24: \[ \frac{1}{8} = \frac{3}{24} \] - Now, we can perform the subtraction: \[ E_C = \frac{3}{24} - \frac{1}{24} = \frac{2}{24} = \frac{1}{12} \] 6. **Calculating the Time Taken by C to Finish the Job Alone:** - If C's efficiency is \( \frac{1}{12} \), it means C can complete \( \frac{1}{12} \) of the job in one day. - Therefore, the time taken by C to finish the entire job alone is: \[ \text{Time} = \frac{\text{Total Work}}{\text{Efficiency of C}} = \frac{1}{\frac{1}{12}} = 12 \text{ days} \] ### Conclusion: C alone will finish the job in **12 days**. ---
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