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S can do a piece of work in 80 days and ...

S can do a piece of work in 80 days and T in 60 days. With the help of U, they finish the work in 20 days. In how many days U alone can do the same work?

A

40

B

60

C

48

D

80

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first determine the work done by S, T, and U, and then find out how long U alone would take to complete the work. ### Step 1: Determine the work done by S and T - S can complete the work in 80 days. - T can complete the work in 60 days. To find the work done by each in one day, we can use the formula: \[ \text{Work done in one day} = \frac{1}{\text{Number of days to complete the work}} \] - Work done by S in one day: \[ \text{Work by S} = \frac{1}{80} \text{ of the work} \] - Work done by T in one day: \[ \text{Work by T} = \frac{1}{60} \text{ of the work} \] ### Step 2: Calculate the combined work done by S and T in one day To find the combined work done by S and T in one day, we add the work done by both: \[ \text{Combined work by S and T} = \frac{1}{80} + \frac{1}{60} \] To add these fractions, we need a common denominator. The least common multiple (LCM) of 80 and 60 is 240. Converting the fractions: \[ \frac{1}{80} = \frac{3}{240} \quad \text{and} \quad \frac{1}{60} = \frac{4}{240} \] Now, adding these: \[ \text{Combined work by S and T} = \frac{3}{240} + \frac{4}{240} = \frac{7}{240} \] ### Step 3: Determine the total work done by S, T, and U together We know that S, T, and U together finish the work in 20 days. Therefore, the work done by all three in one day is: \[ \text{Combined work by S, T, and U} = \frac{1}{20} \] ### Step 4: Set up the equation to find U's work Now, we can set up the equation: \[ \text{Work by S} + \text{Work by T} + \text{Work by U} = \text{Combined work by S, T, and U} \] Substituting the values we found: \[ \frac{7}{240} + \text{Work by U} = \frac{1}{20} \] ### Step 5: Convert \(\frac{1}{20}\) to a fraction with a denominator of 240 To solve for U's work, we convert \(\frac{1}{20}\) to have a denominator of 240: \[ \frac{1}{20} = \frac{12}{240} \] ### Step 6: Solve for U's work Now we substitute this back into the equation: \[ \frac{7}{240} + \text{Work by U} = \frac{12}{240} \] Subtract \(\frac{7}{240}\) from both sides: \[ \text{Work by U} = \frac{12}{240} - \frac{7}{240} = \frac{5}{240} \] ### Step 7: Determine how many days U alone would take to complete the work Since U does \(\frac{5}{240}\) of the work in one day, we can find out how many days U would take to complete the entire work: \[ \text{Days taken by U} = \frac{240}{5} = 48 \text{ days} \] ### Final Answer U alone can complete the work in **48 days**. ---
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