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If 10 men or 20 women or 40 children can...

If 10 men or 20 women or 40 children can do a piece of work in 7 months, then 5 men, 5 women and 5 children together can do half of the work in :

A

6 months

B

4 months

C

5 months

D

8 months

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine how long it will take for 5 men, 5 women, and 5 children to complete half of the work. ### Step 1: Determine the work done by each group in one month We know that: - 10 men can complete the work in 7 months. - 20 women can complete the work in 7 months. - 40 children can complete the work in 7 months. Let's calculate the work done by each group in one month. 1. **Work done by 10 men in one month:** \[ \text{Work done by 10 men in 7 months} = 1 \text{ (whole work)} \] \[ \text{Work done by 10 men in 1 month} = \frac{1}{7} \] Therefore, the work done by 1 man in one month is: \[ \text{Work done by 1 man in 1 month} = \frac{1}{7} \div 10 = \frac{1}{70} \] 2. **Work done by 20 women in one month:** \[ \text{Work done by 20 women in 7 months} = 1 \text{ (whole work)} \] \[ \text{Work done by 20 women in 1 month} = \frac{1}{7} \] Therefore, the work done by 1 woman in one month is: \[ \text{Work done by 1 woman in 1 month} = \frac{1}{7} \div 20 = \frac{1}{140} \] 3. **Work done by 40 children in one month:** \[ \text{Work done by 40 children in 7 months} = 1 \text{ (whole work)} \] \[ \text{Work done by 40 children in 1 month} = \frac{1}{7} \] Therefore, the work done by 1 child in one month is: \[ \text{Work done by 1 child in 1 month} = \frac{1}{7} \div 40 = \frac{1}{280} \] ### Step 2: Calculate the total work done by 5 men, 5 women, and 5 children in one month Now, we can find the total work done by 5 men, 5 women, and 5 children in one month: - Work done by 5 men in one month: \[ 5 \times \frac{1}{70} = \frac{5}{70} = \frac{1}{14} \] - Work done by 5 women in one month: \[ 5 \times \frac{1}{140} = \frac{5}{140} = \frac{1}{28} \] - Work done by 5 children in one month: \[ 5 \times \frac{1}{280} = \frac{5}{280} = \frac{1}{56} \] ### Step 3: Combine the work done by all groups Now, we add the work done by 5 men, 5 women, and 5 children in one month: \[ \text{Total work done in one month} = \frac{1}{14} + \frac{1}{28} + \frac{1}{56} \] To add these fractions, we need a common denominator. The least common multiple of 14, 28, and 56 is 56. - Convert each fraction: \[ \frac{1}{14} = \frac{4}{56}, \quad \frac{1}{28} = \frac{2}{56}, \quad \frac{1}{56} = \frac{1}{56} \] - Now add them: \[ \frac{4}{56} + \frac{2}{56} + \frac{1}{56} = \frac{7}{56} = \frac{1}{8} \] ### Step 4: Determine the time to complete half of the work Since 5 men, 5 women, and 5 children together can complete \(\frac{1}{8}\) of the work in one month, we need to find out how long it will take them to complete half of the work (\(\frac{1}{2}\)): \[ \text{Time to complete half of the work} = \frac{\frac{1}{2}}{\frac{1}{8}} = \frac{1}{2} \times 8 = 4 \text{ months} \] ### Final Answer: Thus, 5 men, 5 women, and 5 children together can do half of the work in **4 months**. ---
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