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In an isosceles DeltaABC, AD is the medi...

In an isosceles `DeltaABC, AD `is the median to the unequal side meeting BC at D. DP, is the angle bi sector of `/_ADB `and `PQ` is drawn parallel to BC meeting AC at Q. Then the measure of `/_PDO `is :

A

`130^@`

B

`90^@`

C

`180^@`

D

`45^@`

Text Solution

Verified by Experts

The correct Answer is:
B
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