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If O is the orthocentre of a triangle AB...

If O is the orthocentre of a triangle `ABC `and `/_BOC = 100^@`, the measure of `/_BAC` is

A

`100^@`

B

`180^@`

C

`80^@`

D

`200^@`

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AI Generated Solution

The correct Answer is:
To find the measure of angle \( \angle BAC \) in triangle \( ABC \) where \( O \) is the orthocenter and \( \angle BOC = 100^\circ \), we can use the property of the angles related to the orthocenter. ### Step-by-Step Solution: 1. **Identify the Given Information**: - We know that \( O \) is the orthocenter of triangle \( ABC \). - We are given that \( \angle BOC = 100^\circ \). 2. **Use the Property of Angles at the Orthocenter**: - A key property of the angles in a triangle involving the orthocenter states that: \[ \angle BOC + \angle BAC = 180^\circ \] - This means that the sum of the angle \( BOC \) and the angle \( BAC \) is equal to \( 180^\circ \). 3. **Substitute the Known Value**: - We can substitute the known value of \( \angle BOC \) into the equation: \[ 100^\circ + \angle BAC = 180^\circ \] 4. **Solve for \( \angle BAC \)**: - Rearranging the equation to find \( \angle BAC \): \[ \angle BAC = 180^\circ - 100^\circ \] \[ \angle BAC = 80^\circ \] 5. **Conclusion**: - Therefore, the measure of \( \angle BAC \) is \( 80^\circ \). ### Final Answer: The measure of \( \angle BAC \) is \( 80^\circ \). ---
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