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The number of sides in two regular polyg...

The number of sides in two regular polygons are in the ratio 5:4 and the difference between each interior angle of the polygons is `6^@`. Then the number of sides are.

A

15, 12

B

5, 4

C

10, 8

D

20, 16

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The correct Answer is:
To solve the problem, we need to find the number of sides in two regular polygons given that their sides are in the ratio 5:4 and the difference between their interior angles is 6 degrees. ### Step-by-Step Solution: 1. **Define the Number of Sides:** Let the number of sides of the first polygon be \( n_1 = 5x \) and the number of sides of the second polygon be \( n_2 = 4x \), where \( x \) is a common multiplier. **Hint:** Start by expressing the number of sides in terms of a variable to represent the ratio. 2. **Formula for Interior Angle:** The formula for the interior angle of a regular polygon with \( n \) sides is given by: \[ \text{Interior angle} = \frac{180(n - 2)}{n} \] 3. **Calculate Interior Angles:** For the first polygon (with \( n_1 = 5x \)): \[ \text{Interior angle of first polygon} = \frac{180(5x - 2)}{5x} \] For the second polygon (with \( n_2 = 4x \)): \[ \text{Interior angle of second polygon} = \frac{180(4x - 2)}{4x} \] 4. **Set Up the Equation:** According to the problem, the difference between the interior angles is 6 degrees: \[ \frac{180(5x - 2)}{5x} - \frac{180(4x - 2)}{4x} = 6 \] 5. **Simplify the Equation:** To simplify, we can multiply through by \( 20x \) (the least common multiple of \( 5x \) and \( 4x \)): \[ 20x \left( \frac{180(5x - 2)}{5x} \right) - 20x \left( \frac{180(4x - 2)}{4x} \right) = 20x \cdot 6 \] This simplifies to: \[ 7200(5x - 2) - 9000(4x - 2) = 120x \] 6. **Expand and Combine Like Terms:** Expanding both sides: \[ 36000x - 14400 - 36000x + 18000 = 120x \] Combine like terms: \[ 36000x - 36000x + 18000 - 14400 = 120x \] This simplifies to: \[ 3600 = 120x \] 7. **Solve for \( x \):** Divide both sides by 120: \[ x = \frac{3600}{120} = 30 \] 8. **Find the Number of Sides:** Now substitute \( x \) back to find \( n_1 \) and \( n_2 \): \[ n_1 = 5x = 5 \cdot 30 = 150 \] \[ n_2 = 4x = 4 \cdot 30 = 120 \] 9. **Final Answer:** The number of sides in the two polygons are 150 and 120. ### Summary of Results: - The first polygon has 150 sides. - The second polygon has 120 sides.
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