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ABCD is a rhombus, AB is extended to F a...

ABCD is a rhombus, AB is extended to F and BA to E such that AB = AE = BF then what is the result?

A

`ED gt CF`

B

`ED_I_CF`

C

`ED^2 + CF^2 = EF^2`

D

`ED||CF`

Text Solution

Verified by Experts

The correct Answer is:
B
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