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In a quadrilateral ABCD, the bisectors o...

In a quadrilateral ABCD, the bisectors of `/_A` and `/_B` meet at O. If `/_C = 70^@ and /_D= 130^@`, then measure of `/_AOB `is

A

`40^@`

B

`60^@`

C

`80^@`

D

`100^@`

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The correct Answer is:
To find the measure of angle AOB in quadrilateral ABCD, where the angle bisectors of angles A and B meet at point O, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Angles**: We know that: - Angle C = 70° - Angle D = 130° 2. **Use the Angle Sum Property of Quadrilaterals**: The sum of the interior angles of a quadrilateral is 360°. Therefore, we can express the relationship as: \[ \angle A + \angle B + \angle C + \angle D = 360° \] 3. **Substitute Known Values**: Substitute the values of angles C and D into the equation: \[ \angle A + \angle B + 70° + 130° = 360° \] 4. **Simplify the Equation**: Combine the known angles: \[ \angle A + \angle B + 200° = 360° \] Now, isolate the sum of angles A and B: \[ \angle A + \angle B = 360° - 200° = 160° \] 5. **Use the Angle Bisector Theorem**: The angle bisectors of angles A and B meet at point O. The measure of angle AOB can be calculated using the formula: \[ \angle AOB = \frac{\angle C + \angle D}{2} \] 6. **Substitute Values for C and D**: Now substitute the values of angles C and D: \[ \angle AOB = \frac{70° + 130°}{2} \] 7. **Calculate the Result**: Add the angles and divide by 2: \[ \angle AOB = \frac{200°}{2} = 100° \] ### Final Answer: The measure of angle AOB is **100°**. ---
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KIRAN PUBLICATION-GEOMETRY-QUESTIONS ASKED IN PREVIOUS SSC EXAMS (TYPE- XI)
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  10. AB is a diameter of circle with centre O. PQ is a chord which do not c...

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  14. In an isosceles trapezium .

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