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T is a point on the common tangents at P...

T is a point on the common tangents at P of two circles and if TA and TB are respectively the other tangents at A and B to the two circles drawn from the point T then

A

`TA = 2 TB `

B

`TA = TB `

C

`TA = 1/2 TB `

D

`3TA = TB `

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The correct Answer is:
To solve the problem step by step, we will analyze the given information about the two circles and the tangents drawn from point T. ### Step-by-Step Solution: 1. **Identify the Circles and Tangents**: - Let Circle 1 and Circle 2 be the two circles. - Point T lies on the common tangent at point P, which touches both circles. 2. **Draw the Tangents**: - From point T, draw the tangent TA to Circle 1 at point A. - Similarly, draw the tangent TB to Circle 2 at point B. 3. **Use the Tangent Property**: - According to the property of tangents from a point outside a circle, the lengths of the tangents drawn from a single external point to a circle are equal. - Therefore, for Circle 1, we have: \[ TA = TP \] - For Circle 2, we have: \[ TB = TP \] 4. **Set Up the Equations**: - From the first circle, we have: \[ TA = TP \quad \text{(Equation 1)} \] - From the second circle, we have: \[ TB = TP \quad \text{(Equation 2)} \] 5. **Equate the Tangents**: - Since both TA and TB are equal to TP, we can equate them: \[ TA = TB \] 6. **Conclusion**: - Therefore, the lengths of the tangents from point T to both circles are equal: \[ TA = TB \] ### Final Answer: The correct conclusion is that \( TA = TB \).
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