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In DeltaABC, the angle bisector of angle...

In `DeltaABC`, the angle bisector of `angleBAC` cut BC at D and meet the circumcircle of `DeltaABC` at E. If AB : AD = 3 : 5 then find AE : AC?

A

`5:3`

B

`3:2`

C

`2:3`

D

`3:5 `

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The correct Answer is:
D
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