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In DeltaABC, /A + /B = 145^@ and /C + 2/...

In `DeltaABC, /_A + /_B = 145^@` and `/_C + 2/_B = 180^@`. State which one of the following relations is true ?

A

`CA = AB `

B

`CA gt AB`

C

`BC lt AB `

D

`CA gt AB `

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The correct Answer is:
To solve the problem, we need to analyze the given conditions about the angles in triangle ABC. ### Step-by-Step Solution: 1. **Given Information**: - \( \angle A + \angle B = 145^\circ \) (Equation 1) - \( \angle C + 2\angle B = 180^\circ \) (Equation 2) 2. **Express \( \angle A \) in terms of \( \angle B \)**: From Equation 1: \[ \angle A = 145^\circ - \angle B \] 3. **Express \( \angle C \) in terms of \( \angle B \)**: From Equation 2: \[ \angle C = 180^\circ - 2\angle B \] 4. **Use the angle sum property of a triangle**: The sum of angles in a triangle is \( 180^\circ \): \[ \angle A + \angle B + \angle C = 180^\circ \] Substituting the expressions for \( \angle A \) and \( \angle C \): \[ (145^\circ - \angle B) + \angle B + (180^\circ - 2\angle B) = 180^\circ \] 5. **Simplify the equation**: Combine like terms: \[ 145^\circ + 180^\circ - 2\angle B = 180^\circ \] \[ 325^\circ - 2\angle B = 180^\circ \] 6. **Isolate \( \angle B \)**: Rearranging gives: \[ 325^\circ - 180^\circ = 2\angle B \] \[ 145^\circ = 2\angle B \] \[ \angle B = \frac{145^\circ}{2} = 72.5^\circ \] 7. **Find \( \angle A \)**: Substitute \( \angle B \) back into the expression for \( \angle A \): \[ \angle A = 145^\circ - 72.5^\circ = 72.5^\circ \] 8. **Find \( \angle C \)**: Substitute \( \angle B \) back into the expression for \( \angle C \): \[ \angle C = 180^\circ - 2(72.5^\circ) = 180^\circ - 145^\circ = 35^\circ \] 9. **Analyze the angles**: We have: - \( \angle A = 72.5^\circ \) - \( \angle B = 72.5^\circ \) - \( \angle C = 35^\circ \) 10. **Determine the relationship between the sides**: Since \( \angle A = \angle B \), sides opposite these angles (BC and AC) are equal: \[ BC = AC \] Since \( \angle C \) is the smallest angle, the side opposite \( \angle C \) (AB) is the smallest side: \[ AB < AC \quad \text{and} \quad AB < BC \] ### Conclusion: The correct relation is: - \( AC > AB \) and \( BC > AB \)
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