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A tree of height 'h' metres is broken by...

A tree of height 'h' metres is broken by a storm in such a way that its top touches the ground at a distance of 'x' metres from its root. Find the height at which the tree is broken. (Here `h gt x`)

A

A)`(h^2 + x^2)/(2h)` metre

B

B)`(h^2 - x^2)/(2h)` metre

C

C)`(h^2 + x^2)/(4h)` metre

D

D)`(h^2 - x^2)/(4h)` metre

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The correct Answer is:
To solve the problem of finding the height at which the tree is broken, we can follow these steps: ### Step 1: Understand the Problem We have a tree of height \( h \) meters that is broken at a certain height \( y \). The top of the tree now touches the ground at a distance \( x \) meters from the base of the tree. ### Step 2: Set Up the Triangle When the tree breaks, it forms a right triangle: - The height of the broken part of the tree is \( y \) (the height at which the tree is broken). - The distance from the base of the tree to the point where the top touches the ground is \( x \). - The length of the broken tree from the break point to the top is \( h - y \). ### Step 3: Apply the Pythagorean Theorem In the right triangle formed, we can apply the Pythagorean theorem: \[ AB^2 + BC^2 = AC^2 \] Where: - \( AB = y \) (the height at which the tree is broken), - \( BC = x \) (the distance from the base to the point where the top touches the ground), - \( AC = h - y \) (the remaining height of the tree). Substituting these values into the equation gives: \[ y^2 + x^2 = (h - y)^2 \] ### Step 4: Expand the Equation Now, we expand the right side of the equation: \[ y^2 + x^2 = h^2 - 2hy + y^2 \] ### Step 5: Simplify the Equation Next, we can simplify the equation by canceling \( y^2 \) from both sides: \[ x^2 = h^2 - 2hy \] ### Step 6: Rearrange to Solve for \( y \) Rearranging the equation gives: \[ 2hy = h^2 - x^2 \] Now, divide both sides by \( 2h \): \[ y = \frac{h^2 - x^2}{2h} \] ### Final Answer Thus, the height at which the tree is broken is: \[ y = \frac{h^2 - x^2}{2h} \]
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