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If y = n^x, n > 0 then dy/dx is equal to...

If `y = n^x, n > 0` then `dy/dx` is equal to

A

`xn^(x-1)`

B

`(x)/(logn)`

C

`n^(x)logn`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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