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Distance between the planes 2x + 3y + 4z...

Distance between the planes `2x + 3y + 4z = 4` and `4x + 6y + 8z = 12` is :

A

2 units

B

4 units

C

8 units

D

`(2)/(sqrt29)` units

Text Solution

Verified by Experts

The correct Answer is:
D
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