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If x,y,z are different and Delta= {:|(x,...

If x,y,z are different and `Delta= {:|(x,x^2,1+x^3),(y,y^2,1+y^3),(z,z^2,1+z^3)|=0`, show that xyz=-1

Answer

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If x,y,z are different and Delta=|(x,x^2,1+x^3),(y,y^2,1+y^3),(z,z^2,1+z^3)|=0 then show that 1+xyz=0

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Knowledge Check

  • If x, y, z are all distinct and |(x,x^(2),1+x^(3)),(y,y^(2),1+y^(3)),(z,z^(2),1+z^(3))|=0 then value of x y z is :

    A
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    B
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    C
    1
    D
    2
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    Prove that abs{:(x, x^2 , 1 + px^3),(y , y^2, 1+ py^3),(z, z^2, 1+ pz^3):}= (1 +pxyz) ( x-y) ( y-z) ( z-x) , where p is any scalar.

    Prove that abs{:(x, x^2 , 1 + px^3),(y , y^2, 1+ py^3),(z, z^2, 1+ pz^3):}= (1 +pxyz) ( x-y) ( y-z) ( z-x) , where p is any scalar.

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